A ball is thrown vertically upward from the top of a building96 feet tall with an initial velocity of 80 feet per second. Thedistance s (in feet) of the ball from the ground after t secondsis s = 96 +80t - 16t^2.

a) After how many seconds does the ball strike the ground?
b) After how many seconds will the ball pass the top of thebuilding on its way down?

I'm having trouble with this and know that I have to use thequadratic equation but I'm lost through out.Please help me.

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