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help!!! simplify do not use negative exponents in the answer 12a 5th power / 2a 8th power

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\[12a ^{5}\2a ^{8}\] real problem
Just to be clear, is this what you mean? \[\frac{12a^{5}}{2a^{8}}\]

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Okay, are you able to solve it *with* negative exponents?
I did not know how to make the line on here
\frac{top}{bottom} Do that in the Equation editor, or within \[ and \ ]
nope it said do not use neg exponents and the 5 is -5 and the 8 is -8
I know, but once we get to the final answer *with* negative exponents, we can get rid of them by re-writing the answer.
Wait, are you saying it's to the power of -5 and -8?
Which is correct—top or bottom? \[\frac{12a^{5}}{2a^{8}}\] \[\frac{12a^{-5}}{2a^{-8}}\]
Okay, great. And there are no brackets, right? It's not \((12a)^{-5}\)?
So, to start, are you able to simplify the equation?
I could not find an exmaple in the book like mines so one of the problems in the exercise is like my real problem i need help to figure it out so i can solve mines
Do you know how to simplify exponents?
When dividing like bases (in this case, \(a\)), you subtract the bottom exponent from the top. So, \(a^{(-5)-(-8)}\).
As for your numeric constants, you just divide them (\(12 \div 2\))
ok so that will be -13
No, it's (-5) - (-8).
12/2 is 6 -5-(-8)=3
A double-negative is a positive (in math).
So what's your final answer?
6a\[6a ^3\]
do I do the samething if my problem has 12 x top and 8y bottom
Do you mean like: \(\Large{\frac{12x}{8y}}\) ? No, those are different variables, so you cannot divide one by the other.
You can simplify the numbers \(\Large{\frac{12}{8} = \frac{3}{2}}\), but that's all.
yes with -6 at the top and -10 at the bottom
Ahh, so: \[\frac{12x^{-6}}{8y^{-10}}\] Nope, all you can simplify in this case is 12/8.
Yes, with the same exponents.
so there isn't any steps to break it down because my teacher keep saying show your work
If they're different variables, you can't simplify them further.
The only "work" you could show is dividing both the top and bottom by 4, to simplify your numeric fraction.
\[\Large\frac{12x^{-6}}{8y^{-10}} \small\frac{\div 4}{\div 4}\]

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