vectors/magnitude; trig-based physics; please help!

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At a picnic, there is a contest in which hoses are used toshoot water at a beach ball from three directions. As a result,three forces act on the ball, , , and (see the drawing). Themagnitudes are = 26.0 newtons (N) and = 61.0 N. Determine (a) themagnitude of and (b) theangle θ such that the resultant force acting on theball is zero.
I don't really know where to start here. I don't knowhow to figure out what my equation would be in terms of which in the x direction would be equal to 61 N andin the y direction equal to 26 N?
This is how I worked out the problem, but got theproblem wrong:
x direction: -cosθ + 61=0;so cosθ=61
y direction: -sinθ + 26 = 0; so sinθ=26
then, = 61/cosθ where (61/cosθ)sinθ=26
so, tanθ=26/61; then θ=tan-1(26/61) = 23.085 degrees
then I did....
=61/cosθ=61/cos(23.085)= 66.31 N
Could anyone be of further assistance? I think I justmight be confusing myself even further. Step-by-step would begreatly appreciated as I have no clue even where to begin? Thanks!

Answers (1)

  • Antony08
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