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Answers by Michael W.

Solve algebraically 3x^2/2=2(x-1) (answer)

The first step would be to get rid of any denominators, so multiply both sides of the equation by 2 (what you do to one side of an equation you need to do to the other to maintain equality).   2*(3x^2)/2 = 2*(2(x-1)) and you get 3x^2 = 4(x-1)   Now get rid of the parentheses by distributing...

p1=(5,2);p2=4,6) (answer)

These two points are the hypotenuse of a right triangle. You can then make use of Pythagorean theorem to resolve. One leg is the vertical change (y coordinates) and the other is the horizontal change (x coordinates). (y1-y2)^2 + (x1-x2)^2 = c^2   (2-6)^2 + (5-4)^2 = c^2   (4)^2 +...

please help with an algebra problem (answer)

I am hypothesizing this is a question similar to ones one of my students was doing recently. Is (-2,1) a solution for the equations? Is the first equation y=-1/2x?. If it is, then yes, (-2,1) is a solution. If you plug in the values of -2 for x and 1 for y, then both equations work and the point...